Deathslayer7
2010-01-24, 05:30 PM
The van travels over the hill described by
y= -.0015(x^2) + 15
If it has a constant speed of 75 ft/s , determine the x and y components of the van's velocity when x= 50 ft.
then determine the x and y components of the vans acceleration at x=50 ft.
A little help with the first part can help me get the second part.
i just took the derivative as it is to get V(y)= -.0015/2*x where x = 50
then i put it in terms of x and did the same thing but got the wrong answer. Anyone know why? :smallconfused:
note: this is a parabola.
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an a different problem that i got half of:
A particle travels along the circular path x^2 + y^2 = r^2
If the y component of the particle's velocity is V(y)=2*r*cos(2t), determine the x and y components of its acceleration at any instant.
I found the right x acceleration after some math, but wouldnt the y acceleration just be the derivative, which is:
-4*r*sin(2t) since r is constant for a circle. I did this and it said it is wrong. Note it is online hw.
Thanks for any help and more problems will come if i have trouble.
y= -.0015(x^2) + 15
If it has a constant speed of 75 ft/s , determine the x and y components of the van's velocity when x= 50 ft.
then determine the x and y components of the vans acceleration at x=50 ft.
A little help with the first part can help me get the second part.
i just took the derivative as it is to get V(y)= -.0015/2*x where x = 50
then i put it in terms of x and did the same thing but got the wrong answer. Anyone know why? :smallconfused:
note: this is a parabola.
-------------------------------------------------------------------------
an a different problem that i got half of:
A particle travels along the circular path x^2 + y^2 = r^2
If the y component of the particle's velocity is V(y)=2*r*cos(2t), determine the x and y components of its acceleration at any instant.
I found the right x acceleration after some math, but wouldnt the y acceleration just be the derivative, which is:
-4*r*sin(2t) since r is constant for a circle. I did this and it said it is wrong. Note it is online hw.
Thanks for any help and more problems will come if i have trouble.